C program to swap first and last digit of a number

Required knowledge

Logic

Logic to swap first and last digit of a number
Begin:
    read(num)
lastDigit← num % 10;
digits← log10(num);
firstDigit← num / pow(10, digits);

swappedNum← lastDigit * pow(10, digits);
swappedNum← swappedNum + num % pow(10, digits) - lastDigit;
swappedNum← swappedNum + firstDigit;
End

Program

/**
 * C program to swap first and last digit of a number
 */

#include <stdio.h>
#include <math.h>

int main()
{
    int num, swappedNum;
    int firstDigit, lastDigit, digits;

    // Reads a number from user
    printf("Enter any number: ");
    scanf("%d", &num);

    lastDigit = num % 10; //Gets last digit
    digits = (int)log10(num); //Total number of digits - 1
    firstDigit = (int)(num / pow(10, digits)); //Gets the first digit

    swappedNum = lastDigit;
    swappedNum *= (int)pow(10, digits);
    swappedNum += num % ((int)pow(10, digits));
    swappedNum -= lastDigit;
    swappedNum += firstDigit;

    printf("\nOriginal number = %d", num);
    printf("\nNumber after swapping first and last digit: %d", swappedNum);

    return 0;
}

/**
 * C program to swap first and last digit of a number
 */

#include <stdio.h>
#include <math.h>

int main()
{
    int num, swappedNum;
    int firstDigit, lastDigit, digits;

    // Reads a number from user
    printf("Enter any number: ");
    scanf("%d", &num);

    lastDigit = num % 10; //Gets last digit
    digits = (int)log10(num); //Total number of digits - 1
    firstDigit = (int)(num / pow(10, digits)); //Gets the first digit

    swappedNum = lastDigit;
    swappedNum *= (int)round(pow(10, digits));
    swappedNum += num % ((int)round(pow(10, digits)));
    swappedNum -= lastDigit;
    swappedNum += firstDigit;

    printf("\nOriginal number = %d", num);
    printf("\nNumber after swapping first and last digit: %d", swappedNum);

    return 0;
}