Write a C program to count frequency of digits in an integer. How to find frequency of digits in a given number using loop in C programming. Logic to find total occurrences of each digits in a given number in C program.
Example:
Input num: 116540
Output:
Frequency of 0 = 1
Frequency of 1 = 2
Frequency of 2 = 0
Frequency of 3 = 0
Frequency of 4 = 1
Frequency of 5 = 1
Frequency of 6 = 1
Frequency of 7 = 0
Frequency of 8 = 0
Frequency of 9 = 0
How to find last digit of any number in C
How to reverse numbers in C
How to store and retrieve elements from an array in C
Here goes the step-by-step detailed explantion about how you gonna find the frequency of digits in an integer.
Happy coding ;)
Example:
Input num: 116540
Output:
Frequency of 0 = 1
Frequency of 1 = 2
Frequency of 2 = 0
Frequency of 3 = 0
Frequency of 4 = 1
Frequency of 5 = 1
Frequency of 6 = 1
Frequency of 7 = 0
Frequency of 8 = 0
Frequency of 9 = 0
Required knowledge
Basic C programming, Loop, ArrayLogic to find frequency of digits in a number
Before I begin to explain the logic of counting frequency of digits in a given integer. You must have a good understanding of below three concepts -How to find last digit of any number in C
How to reverse numbers in C
How to store and retrieve elements from an array in C
Here goes the step-by-step detailed explantion about how you gonna find the frequency of digits in an integer.
- First of all we need a storage where we can store frequencies of each digits. For that we will be using an integer array of size 10 call it as freq[10]. We have used an array of size 10 because decimal has base 10. There are only 10 digits that makes up any decimal number.
- Next, we need to initialize every element of the array with 0. Assuming that every digit has occurred 0 times.
- Now comes the main logic. Find the last digit of the given number. For that we need to perform modular division by 10 i.e. lastDigit = num % 10 (where num is the number whose frequency of digits is to be found).
- Increment the freq[ lastDigit ]++ by one.
- Now remove the last digit from the num as it isn't needed anymore. Perform num = num / 10.
- Repeat steps 3-5 till num != 0. Finally you will be left with an array freq having the frequency of each digits in that number.
Program to count frequency of digits in an integer
/**
* C program to count frequency of digits in a given number
*/
#include <stdio.h>
#define BASE 10
int main()
{
long long num, n;
int i, lastDigit;
int freq[BASE];
printf("Enter any number: ");
scanf("%lld", &num);
// Initializes frequency array with 0
for(i=0; i<BASE; i++)
{
freq[i] = 0;
}
n = num; //Copies the value of num to n
while(n != 0)
{
// Gets the last digit
lastDigit = n % 10;
// Increments the frequency array
freq[lastDigit]++;
// Removes the last digit from n
n /= 10;
}
printf("Frequency of each digit in %lld is: \n", num);
for(i=0; i<BASE; i++)
{
printf("Frequency of %d = %d\n", i, freq[i]);
}
return 0;
}
Do not confuse with n /= 10. It is same as n = n / 10.
Output
Enter any number: 11203458760011
Frequency of each digit in 11203458760011 is:
Frequency of 0 = 3
Frequency of 1 = 4
Frequency of 2 = 1
Frequency of 3 = 1
Frequency of 4 = 1
Frequency of 5 = 1
Frequency of 6 = 1
Frequency of 7 = 1
Frequency of 8 = 1
Frequency of 9 = 0
Frequency of each digit in 11203458760011 is:
Frequency of 0 = 3
Frequency of 1 = 4
Frequency of 2 = 1
Frequency of 3 = 1
Frequency of 4 = 1
Frequency of 5 = 1
Frequency of 6 = 1
Frequency of 7 = 1
Frequency of 8 = 1
Frequency of 9 = 0
Happy coding ;)
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