Number pattern 43 in C

1
2  4
7  11 16
22 29 37 46
56 67 79 92 106

Required knowledge

Logic to print the given number pattern

1
2  4
7  11 16
22 29 37 46
56 67 79 92 106

1. It contains total N rows (where N is the total number of rows to be printed).
2. Each row contains exactly i columns (where i is the current row number).
3. If you notice about the integers printed in each column. They are in increasing order with increasing difference. The difference between first two integers is 1 followed by a difference of 2, 3, 4, 5 and so on.

Program to print the given number pattern

/**
 * C program to print the given number pattern
 */

#include <stdio.h>

int main()
{
    int i, j, diff, value, N;

    printf("Enter rows: ");
    scanf("%d", &N);

    diff = 1;
    value = 1;

    for(i=1; i<=N; i++)
    {
        for(j=1; j<=i; j++)
        {
            printf("%-3d", value);

            value += diff; // Computes the next value to be printed
            diff++; // Increments the difference
        }

        printf("\n");
    }

    return 0;
}

Screenshot