C program to get value of nth bit of a number

Write a C program to input any number from user and check whether the n^th bit of the given number is set (1) or not (0). How to check whether the n^th bit of a given number is set or unset using bitwise operator in C programming. C program to get the status of n^th bit of a number.

Example:
Input number: 12
Input nth bit number: 2
Output: 2 bit of 12 is set (1).

Required knowledge:

Basic C programming, Bitwise operator, If else
Before continuing to this post, previous two posts are highly recommended - how to check whether the LSB of a number is set or not and how to check whether the MSB of a number is set or not.

Logic:

To get the n^th bit of any number we just need to right shift the number n times and then perform bitwise AND operation with the shifted number and 1. In general you may say (number >> n) & 1.

Program:

/**
 * C program to get the nth bit of a number
 */

#include <stdio.h>

int main()
{
    int num, n, bitStatus;

    //Reads a number from user
    printf("Enter any number: ");
    scanf("%d", &num);

    //Reads the bit number you want to check
    printf("Enter nth bit to check (0-31): ");
    scanf("%d", &n);

    //Shifting bits to right n times and ANDing with 1
    bitStatus = (num >> n) & 1;

    printf("The %d bit is set to %d", n, bitStatus);

    return 0;
}

Happy coding ;)